Answer:
Option A
Explanation:
$Fe^{2+}$(24)=$[Ar] 3d^{6}4s^{0}$ it has 4 unpaired electrons
$Cu^{+}$(28)=$[Ar] 3d^{10}4s^{0}$ it has 0 unpaired electron
$Zn$(30)= $[Ar] 3d^{10} 4s^{2}$ it has 0 unpaired electron
$Ni^{3+}(25)$ =[Ar]$3d^{7} 4s^{0}$ it has 3 unpaired electrons